Answer:[tex]\circ\ \ 36\sqrt{3}[/tex]Step-by-step explanation:[tex]CD=12\times \sin(60) =12\times \frac{\sqrt{3} }{2}[/tex]Important Note:………………………………………………………………………………………ABC is an equilateral triangle because it has 2 angles of measure 60===========================================================According to the note AB = 12Final answer :[tex]\text{Area of triangle ABC} =\frac{AB\times CD}{2}[/tex] [tex]=\frac{12\times 6\sqrt{3} }{2}[/tex] [tex]=\frac{72\sqrt{3} }{2}[/tex] [tex]=36\sqrt{3}[/tex]